What is the pH of a 10^8 M solution of HCl

2 answers

pH = -log(H^+)
pH = -log(10^-8)
pH = -(8)
pH = -8. Yes, that's right. -8. For anything greater than 1M, the pH will be negative; i.e., 1 M is pH = 0. For < 0, pH is -.
oops. I copied a sign wrong. I made the correction (10-8 should have been 10^8). Here is the complete problem.
pH = -log(H^+)
pH = -log(10^8)
pH = -(8)
pH = -8. Yes, that's right. -8. For anything greater than 1M, the pH will be negative; i.e., 1 M is pH = 0. For < 0, pH is -.