Asked by Jessica
Which is the equation of a 20 cm diameter circle with its center at (3, -6)?
(x+3)^2+(y-6)^2=100
(x-3)^2+(y+6)^2=400
(x-3)^2+(y+6)^2=100 <my choice
(x+3)^2+(y-6)^2=400
(x+3)^2+(y-6)^2=100
(x-3)^2+(y+6)^2=400
(x-3)^2+(y+6)^2=100 <my choice
(x+3)^2+(y-6)^2=400
Answers
Answered by
Steve
good work
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