Asked by Kayla
A 1/5 mmol (yes, millimol... no, it isn't a typo_ sample of XeFn h as a mass of 0.311 g. What is the value of n?
The answer is 4, but why?
The answer is 4, but why?
Answers
Answered by
Kayla
omg that should say 1.50 mmol
Answered by
DrRebel
Given 0.311g sample = 1.50 mmole sample = 1.5x10^-4 mole sample
Sample mole weight = (0.311)g/(1.5x10^-4)mol = 207.33 g/mol
fwt(Xe) + n·fwt(F) = 207.33 g/mol
(131.3)g/mol + n·(19.0)g/mol = 207.33g/mol
(n·19)g/mol = (207.33 - 131.3)g/mol
n = [(207.33 - 131.3)g/mol]/(19)g/mol
n = 74.03/19 = 4
XeF4
Sample mole weight = (0.311)g/(1.5x10^-4)mol = 207.33 g/mol
fwt(Xe) + n·fwt(F) = 207.33 g/mol
(131.3)g/mol + n·(19.0)g/mol = 207.33g/mol
(n·19)g/mol = (207.33 - 131.3)g/mol
n = [(207.33 - 131.3)g/mol]/(19)g/mol
n = 74.03/19 = 4
XeF4
Answered by
Kayla
thank you :D
Answered by
DrRebel
You are most welcome...
DrReb(at)g.m.a.i.l.c.o.m
DrReb(at)g.m.a.i.l.c.o.m
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