Asked by Kayla

A 1/5 mmol (yes, millimol... no, it isn't a typo_ sample of XeFn h as a mass of 0.311 g. What is the value of n?
The answer is 4, but why?

Answers

Answered by Kayla
omg that should say 1.50 mmol
Answered by DrRebel
Given 0.311g sample = 1.50 mmole sample = 1.5x10^-4 mole sample
Sample mole weight = (0.311)g/(1.5x10^-4)mol = 207.33 g/mol

fwt(Xe) + n·fwt(F) = 207.33 g/mol
(131.3)g/mol + n·(19.0)g/mol = 207.33g/mol
(n·19)g/mol = (207.33 - 131.3)g/mol
n = [(207.33 - 131.3)g/mol]/(19)g/mol
n = 74.03/19 = 4
 XeF4
Answered by Kayla
thank you :D
Answered by DrRebel
You are most welcome...
DrReb(at)g.m.a.i.l.c.o.m
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