A 1/5 mmol (yes, millimol... no, it isn't a typo_ sample of XeFn h as a mass of 0.311 g. What is the value of n?
The answer is 4, but why?
4 answers
omg that should say 1.50 mmol
Given 0.311g sample = 1.50 mmole sample = 1.5x10^-4 mole sample
Sample mole weight = (0.311)g/(1.5x10^-4)mol = 207.33 g/mol
fwt(Xe) + n·fwt(F) = 207.33 g/mol
(131.3)g/mol + n·(19.0)g/mol = 207.33g/mol
(n·19)g/mol = (207.33 - 131.3)g/mol
n = [(207.33 - 131.3)g/mol]/(19)g/mol
n = 74.03/19 = 4
XeF4
Sample mole weight = (0.311)g/(1.5x10^-4)mol = 207.33 g/mol
fwt(Xe) + n·fwt(F) = 207.33 g/mol
(131.3)g/mol + n·(19.0)g/mol = 207.33g/mol
(n·19)g/mol = (207.33 - 131.3)g/mol
n = [(207.33 - 131.3)g/mol]/(19)g/mol
n = 74.03/19 = 4
XeF4
thank you :D
You are most welcome...
DrReb(at)g.m.a.i.l.c.o.m
DrReb(at)g.m.a.i.l.c.o.m