Asked by Anonymous
if a plate of car consists of two letters and four digits and one car chosen at random probabiliy the letters at the beginning and at the end
Answers
Answered by
Anonymous
there are 6! total arrangement so it = 720
if the plate code is AS1234 and we have A (1234) S or S (1234) A for the numbers possible arrangement is 4!= 24 P(E)= 24/720=1/30
we have two ways P(E) will be 1/15.
if the plate code is AS1234 and we have A (1234) S or S (1234) A for the numbers possible arrangement is 4!= 24 P(E)= 24/720=1/30
we have two ways P(E) will be 1/15.
Answered by
Melkamu
The last answer is 1/30
Answered by
Melkamu
1/15
Answered by
kiyer umer
3488
Answered by
Dagm
I need a detail explanation for this qs
Answered by
Anonymous
How you know from 26 letter and ten numbers which is used to form this car plate? As I think the answers is incorrect.
Answered by
abubeker
we can use permutation to compute, there are 2 ways for the letters and 4 ways for the digits.
Totally there are 6 ways
2!4!/6!= 1/15
Totally there are 6 ways
2!4!/6!= 1/15
Answered by
mr hassen
detail explaining
Answered by
Ermiyas
I need more explanation about how it com
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