if a plate of car consists of two letters and four digits and one car chosen at random probabiliy the letters at the beginning and at the end

Answer 1

there are 6! total arrangement so it = 720
if the plate code is AS1234 and we have A (1234) S or S (1234) A for the numbers possible arrangement is 4!= 24 P(E)= 24/720=1/30
we have two ways P(E) will be 1/15.

Answer 2

The last answer is 1/30

Answer 3

1/15

Answer 4

3488

Answer 5

I need a detail explanation for this qs

Answer 6

How you know from 26 letter and ten numbers which is used to form this car plate? As I think the answers is incorrect.

Answer 7

we can use permutation to compute, there are 2 ways for the letters and 4 ways for the digits.
Totally there are 6 ways

2!4!/6!= 1/15

Answer 8

detail explaining

Answer 9

I need more explanation about how it com