Asked by Eyoseyas
If a plate of car consists of a two letter and four digits and one car is chosen at random, then find the probability that the car has the letter together
Answers
Answered by
oobleck
consider the two letters as one item. Then there are
26^2 * 10^4 possible plates.
The letters and digits can be rearranged in 5! ways, so there are
26^2 * 10^4 * 5! different plates with the letters together.
There are 36^6 possible plates in all, so our probability is
(26^2 * 10^4 * 5!)/36^6 = 0.37266
26^2 * 10^4 possible plates.
The letters and digits can be rearranged in 5! ways, so there are
26^2 * 10^4 * 5! different plates with the letters together.
There are 36^6 possible plates in all, so our probability is
(26^2 * 10^4 * 5!)/36^6 = 0.37266
Answered by
oobleck
actually, that's not quite right, since I did not allow for the fact that if a character is repeated, the plate count has to be reduced. See whet you can do with that.
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