Asked by anu mol
How to calculate number of electrones in 18 ml of water givan that density of water is 1g/cc
Answers
Answered by
DrRebel
HOH => 2 + 8 + 2 = 12 e^-/molecule HOH
=> (12 e^-/molecule)(6.02x1-^23)molecules/mol))(1mol/18g)(1g/ml)
=> ([(12)(6.02x10^23)(1)(1)]/[18])
=> 4x10^23 e^-/18-ml HOH
=> (12 e^-/molecule)(6.02x1-^23)molecules/mol))(1mol/18g)(1g/ml)
=> ([(12)(6.02x10^23)(1)(1)]/[18])
=> 4x10^23 e^-/18-ml HOH