Asked by ben
calculate the number of Mg2+ ions in each mL of 0.162M(molarity) magnesium bromide
Answers
Answered by
Damon
There are 10^-3 liters of MgBr2
There are .162*10^-3 moles therefore
In each mole there are 6*10^23 molecules
so
.162*10^-3 * 6 * 10^23 ions
There are .162*10^-3 moles therefore
In each mole there are 6*10^23 molecules
so
.162*10^-3 * 6 * 10^23 ions
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