Asked by Lilit***

If a 5.26-g sample of copper at 258 °C is placed in 125 mL of water at 21.0 °C, how hot will the water get? Assume no heat loss to the surroundings. The specific heat of copper is 0.385 J/g °C.
Answered by bobpursley
The sum of heats gained is zero (one heat gained will be negative, a loss)

HeatgainedCu+ Heatgainedwater=0
MassCu*specheatCu*(Tf-258)+masswater*cw(Tf-21)=0

solve for Tf
Answered by Lilit***
how do u solve for Tf
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