If a 5.26-g sample of copper at 258 °C is placed in 125 mL of water at 21.0 °C, how hot will the water get? Assume no heat loss to the surroundings. The specific heat of copper is 0.385 J/g °C.

Answer 1

The sum of heats gained is zero (one heat gained will be negative, a loss)

HeatgainedCu+ Heatgainedwater=0
MassCu*specheatCu*(Tf-258)+masswater*cw(Tf-21)=0

solve for Tf

Answer 2

how do u solve for Tf