Asked by danielle
If a 0.192 g sample of copper metal reacts with elemental sulfur to form 0.240 g of the sulfide product, (a) find the percent by mass of copper and sulfur in the product and (b) find the empirical formula of the copper sulfide
Answers
Answered by
DrBob222
0.240g = mss Cu + S compound
-0.192g = mass Cu
---------------
0.048 g = S added to the Cu
%Cu = (mass Cu/mass total)*100 = ?
Take a 100 g sample.
mols Cu = grams/atomic mass Cu
mols S = grams/atomic mass S
Find the ratio of Cu to S with the smaller number being 1.00
Post your work if you get stuck.
%S = (mass S/mass total)*100 = ?
-0.192g = mass Cu
---------------
0.048 g = S added to the Cu
%Cu = (mass Cu/mass total)*100 = ?
Take a 100 g sample.
mols Cu = grams/atomic mass Cu
mols S = grams/atomic mass S
Find the ratio of Cu to S with the smaller number being 1.00
Post your work if you get stuck.
%S = (mass S/mass total)*100 = ?
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