moving beltway at an airport has a speed v1 and a S length L. A woman stands on the beltway as it moves from one end to the other, while a man in a hurry to reach his flight walks on the beltway with a speed of v2 relative to the moving beltway. (a) What time inter- val is required for the woman to travel the distance L? (b) What time interval is required for the man to travel this distance? (c) A second beltway is located next to the first one. It is identical to the first one but moves in the opposite direction at speed v1. Just as the man steps onto the beginning of the beltway and begins to walk at speed v2 relative to his beltway, a child steps on the other end of the adjacent beltway. The child stands at rest relative to this second beltway. How long after
stepping on the beltway does the man pass the child
For part a its simple : L/v1
For part b the mans velocity will be v1+v2/L
The thing that is confusing me is part C this is what I get:
Man: Xf = Xi + Vxt + 1/2at^2
L = (V2+V1)t
Child : -L = -Vit
(V2+v2)t= Vit
???????? So im confused here
1 answer
, how do I solve for t?