C5H12 + O2--- CO2 + H2O give that the equation if I use 85 grams of O2 and excess C5H12 how many grams of CO2 are produced

Answer 1

C5H12 + 8O2--- 5CO2 + 6H2O

mols O2 = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols O2 to mols CO2.
Then g CO2 = mols CO2 x molar mass CO2

Answer 2

Balanced equation
C5H12 + 8O2 --> 5CO2 + 6H2O