Question
Pentane (C5H12) burns in oxygen to produce carbon dioxide and water.
C5H12(g)+8O2(g)→5CO2(g)+6H2O(g)
Calculate the mass of CO2 that can be produced if the reaction of 38.5 g of pentane and sufficient oxygen has a 58.0 % yield.
C5H12(g)+8O2(g)→5CO2(g)+6H2O(g)
Calculate the mass of CO2 that can be produced if the reaction of 38.5 g of pentane and sufficient oxygen has a 58.0 % yield.
Answers
mols pentane = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols pentane to mols CO2.
Then g CO2 = mols CO2 x molar mass CO2 and this is the mass at 100% yield.
Mass CO2 at 58.0% yield is mass at 100% yield x 0.580 = ?
Using the coefficients in the balanced equation, convert mols pentane to mols CO2.
Then g CO2 = mols CO2 x molar mass CO2 and this is the mass at 100% yield.
Mass CO2 at 58.0% yield is mass at 100% yield x 0.580 = ?
What was the answer exactly?
CO and H2O
Sodium bicarbonate in an reacts with hydrochloric acid to form carbon dioxide sodium chloride and water
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