Asked by Alex
Pentane (C5H12) burns in oxygen to produce carbon dioxide and water.
C5H12(g)+8O2(g)→5CO2(g)+6H2O(g)
Calculate the mass of CO2 that can be produced if the reaction of 38.5 g of pentane and sufficient oxygen has a 58.0 % yield.
C5H12(g)+8O2(g)→5CO2(g)+6H2O(g)
Calculate the mass of CO2 that can be produced if the reaction of 38.5 g of pentane and sufficient oxygen has a 58.0 % yield.
Answers
Answered by
DrBob222
mols pentane = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols pentane to mols CO2.
Then g CO2 = mols CO2 x molar mass CO2 and this is the mass at 100% yield.
Mass CO2 at 58.0% yield is mass at 100% yield x 0.580 = ?
Using the coefficients in the balanced equation, convert mols pentane to mols CO2.
Then g CO2 = mols CO2 x molar mass CO2 and this is the mass at 100% yield.
Mass CO2 at 58.0% yield is mass at 100% yield x 0.580 = ?
Answered by
Karla
What was the answer exactly?
Answered by
Will Cockerham
CO and H2O
Answered by
Anonymous
Sodium bicarbonate in an reacts with hydrochloric acid to form carbon dioxide sodium chloride and water
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