Asked by henro
solve using first differenciation principle
1)y=e^sinx
1)y=e^sinx
Answers
Answered by
AMELIA
the derivative of e^f(x)= e^f(x) . d/dx [f(x)]
therefore
y=e^sinx = e^sinx . cosx
therefore
y=e^sinx = e^sinx . cosx
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