Asked by henry3
solve using first principle of differenciation
1)y=e^3x
2)y=1/3(x^2)^1/2
1)y=e^3x
2)y=1/3(x^2)^1/2
Answers
Answered by
AMELIA
the derivative of e^f(x)= e^f(x) . d/dx [f(x)]
therefore
y'=e^3x.3
2) use chain rule
y'=1/6(x^2)^-1/2 . 2x
therefore
y'=e^3x.3
2) use chain rule
y'=1/6(x^2)^-1/2 . 2x
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