Asked by henry1
solve using first principle of differenciation
1)y=sin{square root(x)}
1)y=sin{square root(x)}
Answers
Answered by
Steve
start with the sum-to-product formula:
sin(√(x+h))-sin(√x)
= 2cos((√(x+h)+√x))/2)sin((√(x+h)-√x)/2)
or, try substituting u = √x
sin(√x) = √x sin(√x) / √x = u * sin(u)/u
and you know that lim sin(u)/u = 1
sin(√(x+h))-sin(√x)
= 2cos((√(x+h)+√x))/2)sin((√(x+h)-√x)/2)
or, try substituting u = √x
sin(√x) = √x sin(√x) / √x = u * sin(u)/u
and you know that lim sin(u)/u = 1
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