Question

A body is in equilibrium when three forces act on it. Two of the forces are F1 of magnitude 8N acting due east and F2 which is 5N acting N 60degree E. Find the magnitude and direction of the third force.

Answer 1

break up f1 and f2 into components, then f3 componnets are equal, but opposite directions.

F1+F2=8E +5cos60N+5sin60E
= E(8+5*.866)+5*1/2 N

F3=W(8+5*.866) + 2.5 S

Answer 2

thank you bobpursley