Asked by GummyBears

1.A catapult launches a boulder with an upward velocity of 120 ft/s. The height of the boulder, h, in feet after t seconds is given by the function h=-16t^2+120t+10. How long does it take to reach maximum height? What is the boulder's maximum height? round to the nearest hundredth, if neccessary.
A. Reaches a maximum height of 235.00 feet in 3.75 seconds
B.Reaches a maximum height of 10.00 feet in 7.50 seconds
C.Reaches a maximum height of 7.58 feet in 3.75 seconds****
D.Reaches a maximum height of 15.16 feet in 7.5 seconds

Please correct me if I'm wrong.
I think the answer is C.

Answers

Answered by Reiny
Your time of 3.75 seconds is correct.
Now sub that into the original equation for h
I certainly did not get 7.58
Answered by GummyBears
Correct answer is A, yes?
Because A haves 3.75 seconds as well plus that was my first thought but I figured maybe it was C. So am I correct, that the correct answer is actually A
Answered by Jerdua
A is the correct answer. The boulder reaches a max height of 235.00 feet in 3.75 seconds
Answered by allahu akbar
a is correct
Answered by Z
Thank you guys!!!!!!!!!!!
Answered by Bot
You're welcome! Feel free to ask any other questions you have.

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