Question

. A catapult launches a boulder with an upwark velocity pf 184 feet per second. the heigh of the boulder in feet after t seconds is given by the function h(t)=-16t^2+184t+20. how long does it take the boulder to reach its maximum height? What is the boulders maximum height? Round to the nearest hundredth.
Reaches a maximum height of 11.6 feet after 5.75
Reaches a maximum height of 549 feet after 11.5 seconds
Reaches a maximum height of 549 feet after 5.75 seconds
Reaches a maximum height of 23.2 feet after 11.6 seconds. <---- My answer

Does anyone know if i'm correct?

Answer 1

Mrs sue or Damon am I correct?

Answer 2

the x of the vertex is -b/(2a) = -184/(-32)
= 5.75 seconds

plug that into the function
h(5.75) = 16(5.75^2) + 184(5.75) + 20
= 549 ft