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2ZnS + 3O2 -> 2ZnO + 2SO2

If 1000kg of ZnS is oxidised, what amount (in moles) and volume (in litres) of SO2 is produced (assuming that gas is at STP)

1 answer

the formula for calculating the number of moles:
n=m/M
The formula for calculating the volume (at STP):
v=n.22,4
n(Zn)=1000.1000/97 moles
n(SO2)=n(Zn) = 1000.1000/97 moles
V(SO2) = 1000.1000.22,4/97=230927,8351 (in litres)