Asked by Casey
2ZnS + 3O2 -> 2ZnO + 2SO2
If 1000kg of ZnS is oxidised, what amount (in moles) and volume (in litres) of SO2 is produced (assuming that gas is at STP)
If 1000kg of ZnS is oxidised, what amount (in moles) and volume (in litres) of SO2 is produced (assuming that gas is at STP)
Answers
Answered by
Athenal
the formula for calculating the number of moles:
n=m/M
The formula for calculating the volume (at STP):
v=n.22,4
n(Zn)=1000.1000/97 moles
n(SO2)=n(Zn) = 1000.1000/97 moles
V(SO2) = 1000.1000.22,4/97=230927,8351 (in litres)
n=m/M
The formula for calculating the volume (at STP):
v=n.22,4
n(Zn)=1000.1000/97 moles
n(SO2)=n(Zn) = 1000.1000/97 moles
V(SO2) = 1000.1000.22,4/97=230927,8351 (in litres)
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