Asked by Madalyn
Given the equation 2SO2(g) +O2(g) -> 2SO3(g), H = -197.8 kJ per Mole, find the quantity of heat transferred when 8.54 grams of sulfur dioxide react completely.
I'm stuck. Please help >-<
I'm stuck. Please help >-<
Answers
Answered by
bobpursley
molmass SO2=64g (check that)
8.54/(64)=Heat/(-197.8kJ)
8.54/(64)=Heat/(-197.8kJ)
Answered by
DrBob222
The equation tells you that 2 mols SO2 will generate 197.8 kJ. How much is 2 mols SO2? That's 2*64 = 128 g SO2 will generate 197.8 kJ. So what will 8.54 g do? Set up a ratio/proportion or use reason to do it. Here is ratio/proportion:
(128 g/197.8 kJ) = 8.54 g/x kJ). Solve for x.
Reason:
197.8 kJ x (8.54/128) = ?
(128 g/197.8 kJ) = 8.54 g/x kJ). Solve for x.
Reason:
197.8 kJ x (8.54/128) = ?
Answered by
DrBob222
Sorry I posted too. I was almost through answering when the phone rang and when the conversation was over I didn't check if the question had been answered.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.