Asked by Lauren
                An arrow is fired at an angle of 53 with a velocity of 15 m/s. 
what is its range?
explain step by step please!!
            
        what is its range?
explain step by step please!!
Answers
                    Answered by
            Lauren
            
    and...the time is 3.06s
    
                    Answered by
            bobpursley
            
    if it is fired from the ground, and hits the ground, then
distance=vhorizontal*timeinair
but vhorzontal is 15cos53 or 9.03m/s
time in the air is given, I think as 3.06 seconds.
Now checking the time in air given. the vertical equation is given as
vfinal=Vinitial-g *time
and vfinal is= - vinitial, so
time= 2Vinitialvertical/g
= 2*15*sin53/9.8=2.44 seconds. Hmmm. I am not certain what then you mean by time is 3.06 seconds
    
distance=vhorizontal*timeinair
but vhorzontal is 15cos53 or 9.03m/s
time in the air is given, I think as 3.06 seconds.
Now checking the time in air given. the vertical equation is given as
vfinal=Vinitial-g *time
and vfinal is= - vinitial, so
time= 2Vinitialvertical/g
= 2*15*sin53/9.8=2.44 seconds. Hmmm. I am not certain what then you mean by time is 3.06 seconds
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.