Asked by Lauren

An arrow is fired at an angle of 53 with a velocity of 15 m/s.

what is its range?
explain step by step please!!
Answered by Lauren
and...the time is 3.06s
Answered by bobpursley
if it is fired from the ground, and hits the ground, then

distance=vhorizontal*timeinair
but vhorzontal is 15cos53 or 9.03m/s

time in the air is given, I think as 3.06 seconds.

Now checking the time in air given. the vertical equation is given as

vfinal=Vinitial-g *time
and vfinal is= - vinitial, so
time= 2Vinitialvertical/g
= 2*15*sin53/9.8=2.44 seconds. Hmmm. I am not certain what then you mean by time is 3.06 seconds
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