An arrow is fired into the air with an initial velocity of 96 feet per second. The height in feet of the arrow t seconds after it was shot into the air is given by the function Find the maximum height of the arrow.

Answer 1

Straight up I hope.

well if so, I happen to have a hunch that the function is

h = Vi t - 16 t^2

and the velocity is given by
v = Vi - 32 t

at the top v = 0
so at top, t = Vi/32 = 96/32 = 3 seconds

then
h = 96 * 3 - 16 (9)
= 144