Asked by Sara
An arrow is fired into the air with an initial velocity of 96 feet per second. The height in feet of the arrow t seconds after it was shot into the air is given by the function Find the maximum height of the arrow.
Answers
Answered by
Damon
Straight up I hope.
well if so, I happen to have a hunch that the function is
h = Vi t - 16 t^2
and the velocity is given by
v = Vi - 32 t
at the top v = 0
so at top, t = Vi/32 = 96/32 = 3 seconds
then
h = 96 * 3 - 16 (9)
= 144
well if so, I happen to have a hunch that the function is
h = Vi t - 16 t^2
and the velocity is given by
v = Vi - 32 t
at the top v = 0
so at top, t = Vi/32 = 96/32 = 3 seconds
then
h = 96 * 3 - 16 (9)
= 144
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