Asked by may
The second term of an arithmetic progression is 8 and the eleventh term is -10 Find the first term, the common differrnce and sum to 15 terms
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Answered by
Steve
the two terms are 9d apart. So, d = -2
Now you have d, and can easily find a, so
S15 = 15/2 (2a + 14d)
Now you have d, and can easily find a, so
S15 = 15/2 (2a + 14d)
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