Asked by Trevor
The second term of an arithmetic progression is 50 and the 5th term is 65.calculate the value of the 40th term
Answers
Answered by
Reiny
a+d = 50
a + 4d=65
subtract them
3d = 15
d = 5
then a+5=50
a=45
term40 = a + 39d = 45 + 39(5) = 240
a + 4d=65
subtract them
3d = 15
d = 5
then a+5=50
a=45
term40 = a + 39d = 45 + 39(5) = 240
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