Question

The second term of an arithmetic progression is 50 and the 5th term is 65.calculate the value of the 40th term

Answer 1

a+d = 50
a + 4d=65
subtract them
3d = 15
d = 5

then a+5=50
a=45

term40 = a + 39d = 45 + 39(5) = 240