A candy machine contains 100 gumballs: 23 grape, 26 blueberry, 16 cherry, and 35 strawberry. What is the experimental probability of choosing a blueberry gumball as a percent and a fraction?
P(blueberry)=# of blueberry gumballs
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total # of gumballs
P(bluebery) = 26/100 = 13/50
The experimental probability of choosing a blueberry gumball is 13/50 or 26%.
P(blueberry)=# of blueberry gumballs
---------------------
total # of gumballs
P(bluebery) = 26/100 = 13/50
The experimental probability of choosing a blueberry gumball is 13/50 or 26%.
Answers
Answered by
Damon
yes, true
thanks
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