Asked by David

DrBobb22

Calcule the concentrations of Cd^+2 , [Cd(CN)4^-2] and CN^- at equilibrium, when 0.42 moles of Cd(NO3)2 dissolves in 1 L of 2.50 M NaCN

Kf for Cd(CN)4^-2

Help!

9 years ago

Answered by David

Kf is 7.1 x 10^16

9 years ago

Answered by DrBob222

If you answered the question I asked I might be able to help.

9 years ago

Answered by David

I will post again ok?

9 years ago

Answered by DrBob222

right. See above for my response.

9 years ago

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Asked by David

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