Asked by David

DrBobb22

Calcule the concentrations of Cd^+2 , [Cd(CN)4^-2] and CN^- at equilibrium, when 0.42 moles of Cd(NO3)2 dissolves in 1 L of 2.50 M NaCN

Kf for Cd(CN)4^-2


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Answered by David
Kf is 7.1 x 10^16

Answered by DrBob222
If you answered the question I asked I might be able to help.
Answered by David
I will post again ok?
Answered by DrBob222
right. See above for my response.
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