Asked by karen
                How many milliliters of concentrated nitric acid, HNO3, 70 % (wt/wt) are required to prepare 1 liter of 0.250 M solution? The molar mass and density of HNO3 are 63.0 g/mol and 1.36 g/cm respectively. 
            
            
        Answers
                    Answered by
            DrBob222
            
    First, what is the M of the 70% HNO3. That's 
1.36 g/mL x 1000 mL x 0.70 x (1/63) = ? M1
Then M1 x mL1 = M2 x mL2
M2 is 0.250; mL2 = 1000 mL, solve for mL1.
    
1.36 g/mL x 1000 mL x 0.70 x (1/63) = ? M1
Then M1 x mL1 = M2 x mL2
M2 is 0.250; mL2 = 1000 mL, solve for mL1.
                    Answered by
            Nur
            
    First, what is the M of the 70% HNO3. That's 
1.36 g/mL x 1000 mL x 0.70 x (1/63) = ? M1
Then M1 x mL1 = M2 x mL2
M2 is 0.250; mL2 = 1000 mL, solve for mL1
    
1.36 g/mL x 1000 mL x 0.70 x (1/63) = ? M1
Then M1 x mL1 = M2 x mL2
M2 is 0.250; mL2 = 1000 mL, solve for mL1
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.