Asked by Crystal
Mdm Lee gave Nathan and Jasper some money on Friday.On Saturday,Nathan gave 1/3 of the amount he had to Jasper.On Sunday,Jasper gave 1/3 of the amount he had to Nathan.In the end,Nathan had $96 and Jasper had $120.How much did each of them have at first?
Answers
Answered by
Steve
Friday: the amounts are
n and j
Saturday:
2n/3 and j+n/3
Sunday:
2n/3 + (1/3)(j+n/3) and (2/3)(j+n/3)
= j/3 + 7n/9 and 2j/3 + 2n/9
so,
j/3 + 7n/9 = 96
2j/3 + 2n/9 = 120
Nathan had $54 and Jasper had $162
I'll let you verify the accuracy of the solution.
n and j
Saturday:
2n/3 and j+n/3
Sunday:
2n/3 + (1/3)(j+n/3) and (2/3)(j+n/3)
= j/3 + 7n/9 and 2j/3 + 2n/9
so,
j/3 + 7n/9 = 96
2j/3 + 2n/9 = 120
Nathan had $54 and Jasper had $162
I'll let you verify the accuracy of the solution.
Answered by
Crystal
I still don't really understand though due to the /
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