Let us take AC=Length of a ladder
BC = Distance between ladder base and wall of a building.
AB = Distance which we have to find out.( A point where ladder rests)
Triangle formed is angle ABC which is right angle triangle.
In angle ABC , AB^2 + BC^2 = AC^2
AB^2 = AC^2 - BC^2
AB^2 = 25^2 - 7^2 = 576
AB = sqrt [ 576 ]
AB = 24 ft high ladder reach high on the building.
a painter leans a 25 foot ladder against a building. The distance from the ground to the top of the ladder is 17 feet more than the distance from the building to the base of the ladder. Find the distance from the building to the base of the ladder and the distance from the ground to the top of the ladder
2 answers
My bad. That was ment for a different post but close to yours 😉
3 answers