Asked by Jen
Determine the exact value if cot(3pi/4) using special triangles.
I don't understand how it could be 1/tan3pi/4 in a triangle....
I don't understand how it could be 1/tan3pi/4 in a triangle....
Answers
Answered by
Steve
for any x,
cot(x) = 1/tan(x)
3pi/4 is in Quadrant II, so draw the triangle.
x = -1
y = 1
cot(3pi/4) = x/y = -1/1 = -1
or, consider that
cot(pi-x) = -cot(x)
since cos(pi-x) = -cos(x)
and sin(pi-x) = sin(x)
so, cot(3pi/4) = cot(pi - pi/4) = -cot(pi/4)
cot(x) = 1/tan(x)
3pi/4 is in Quadrant II, so draw the triangle.
x = -1
y = 1
cot(3pi/4) = x/y = -1/1 = -1
or, consider that
cot(pi-x) = -cot(x)
since cos(pi-x) = -cos(x)
and sin(pi-x) = sin(x)
so, cot(3pi/4) = cot(pi - pi/4) = -cot(pi/4)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.