Asked by Jay
Use the Fundamental Theorem of Calculus to find G'(x) if:
/x²
G(x)= / cos t dt
/
1
/x²
G(x)= / cos t dt
/
1
Answers
Answered by
Steve
change all the t's to x^2, then multiply by (x^2)'
G(x) = cos(x^2)(2x)
G(x) = cos(x^2)(2x)
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