Asked by Anonymous
A 1.8 kg piece of a metal initially at a temperature of 180oC is dropped into the water with mass of 14 kg. The water is in a container made of the same metal with mass 3.6 kg. The initial temperature of the water and container is 16.0oC, and the final temperature of the entire system (including the container) is 18.0oC. Calculate the specific heat of the metal.
Answers
Answered by
bobpursley
the sum of heats gained is zero.
Heatgainedwater+heatgainedmetal=0
14kg*cw*(18.0-16.0)+(1.8+3.6)kg*Cm*(18.0-180)=0
solve for cmetal cm
Heatgainedwater+heatgainedmetal=0
14kg*cw*(18.0-16.0)+(1.8+3.6)kg*Cm*(18.0-180)=0
solve for cmetal cm
Answered by
Francis
I need help I don't know how to solve it
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