Asked by Sarah
((2X-14Cos45)/(49+X^2-14XCos45))+0.3536 = 0
Solve to find the value of X
Change cos 45 to sqrt 2 and rewrite the equation in the form
a x^2 + bx + c = 0
Start out by rewriting it as
2x - 9.8995
= (-0.3536)(49 + x^2 - 9.8995 x)
Conimue until you get the form
a x^2 + bx + c = 0, figure out what a, b, and c are, and use the quadratic equation for the two different values of x that are the roots of the equation.
If you are unfamiliar with the quadratic equation method, review
http://www.chem.tamu.edu/class/fyp/mathrev/mr-quadr.html
Sorry, I made a mistake in my previous answer. Cos 45 should have been (1/2) sqrt 2 = 0.70711.., not sqrt 2. Duh. The procedure is OK; the numbers are wrong.
Solve to find the value of X
Change cos 45 to sqrt 2 and rewrite the equation in the form
a x^2 + bx + c = 0
Start out by rewriting it as
2x - 9.8995
= (-0.3536)(49 + x^2 - 9.8995 x)
Conimue until you get the form
a x^2 + bx + c = 0, figure out what a, b, and c are, and use the quadratic equation for the two different values of x that are the roots of the equation.
If you are unfamiliar with the quadratic equation method, review
http://www.chem.tamu.edu/class/fyp/mathrev/mr-quadr.html
Sorry, I made a mistake in my previous answer. Cos 45 should have been (1/2) sqrt 2 = 0.70711.., not sqrt 2. Duh. The procedure is OK; the numbers are wrong.