Asked by James
Two telephone poles are 60ft. apart, and one of them is 6ft. higher than the other. If the length of the wire between the poles is 61.3 ft., how much wire was allowed for sag?.
Answers
Answered by
Steve
the straight-line distance is
√(60^2+6^2) = 60.3 ft, so ...
√(60^2+6^2) = 60.3 ft, so ...
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