Asked by Kim
Find the area
f(x)=10x/x^2+1, y=0, 0 less than or equal to x less than or equal to < 5
f(x)=10x/x^2+1, y=0, 0 less than or equal to x less than or equal to < 5
Answers
Answered by
Reiny
integral 10x/(x^2 + 1) dx from 0 to 5
= 5ln(x^2 + 1) | from 0 to 5
= 5ln 26 - 5ln1
= 5 ln 26 - 0
= 5 ln 26
= 5ln(x^2 + 1) | from 0 to 5
= 5ln 26 - 5ln1
= 5 ln 26 - 0
= 5 ln 26
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