The preparation of KClO3 follows these equations:

2KMnO4 + 16HCl->2KCl + 2MnCl2 + 5Cl2 (g) + 8H2O

3Cl2 (g) + 6KOH ->KClO3 + 5KCl + 3H2O

1) How many moles of KClO3 are produced by one mole of KMnO4

I think the only link between the two equations is Cl2 but I don't understand how to solve this problem
Thanks for the help

Similar Questions

Chlorine is prepare by the reaction 2KmnO4 + 16Hcl 2Kcl + 2mncl2 + 5cl2 + 8H2O what mass of KmnO4 is required to prepare 500cm3
1. 1 answer
2KMnO4(aq)+16HCl(aq)->2MnCl2(aq)+5Cl2(g)+8H2O(l)+2KCl(aq)A.)the volume of 0.414 M KMnO4 needed to produce 1.66 mol MnCl2 B.) the
1. 1 answer
Calculate the Go for the oxidation of 5 moles of tin in the following balanced reaction.16HCl + 2KMnO4 + 5Sn ---> 5SnCl2 +
1. 3 answers
Chlorine gas may be easily prepared in the lab according to the reaction:2KMnO4(s)+ 16HCl(aq)-> 2 MnCl2(aq)+5Cl2(g)+ 8H2O(l)+
1. 7 answers