Asked by Aly
Emilio left Main Road at 8 A.M and arrived at Lame Lane at 2 P.M. His average for the whole journey was 60 mph. For the first 70% of the trip, he drove at an average speed of 65 mph. For the next 25% of the remaining trip, his average was 54 mph. Find his average speed for the remaining part of the trip.
Since it took him 6 hrs at 60 mph, I got 360 mi for how far it was and 70% of 360 is 252 and 25% is 90 which means the remaining part is 18. I don't know what to do with the 65 and 54.
Since it took him 6 hrs at 60 mph, I got 360 mi for how far it was and 70% of 360 is 252 and 25% is 90 which means the remaining part is 18. I don't know what to do with the 65 and 54.
Answers
Answered by
Steve
he drove for 6 hours at 60 mph, or 360 miles
70% of 360 = 252
25% of 108 = 27
360-(252+27) = 81
since time = distance/speed,
252/65 + 27/54 + 81/x = 6
x = 10530/211 ≈ 49.9 mph
70% of 360 = 252
25% of 108 = 27
360-(252+27) = 81
since time = distance/speed,
252/65 + 27/54 + 81/x = 6
x = 10530/211 ≈ 49.9 mph
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.