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A block of mass 3kg s sliding along the frictionless horizontal surface with a speed of 2m/s.

1. What is the kinetic energy of the block?

2. A wedge is placed in front of the block, forcing the block to climb up the frictionless 30degrees incline and slow to a stop. How far along the incline does the block move before coming to a stop?

Answer 1

1. KE = 0.5M*V^2 = 0.5*3*2^2 = 6 Joules.

2. PE = KE, M*g*h = 6, 3*9.8*h = 6, h = 0.204 m.

sin30 = 0.204/d, d*sin30 = 0.204, d = 0.408 m. = Distance along the incline.