Asked by dt

find the dy/dx of:

y=3(cscx)^3/2
Answered by RJ
First you do powers.

3(csc(x))^1/2

Then trig.

The final:

-3(csc(x))^1/2 *(csc(x)cot(x))

Answered by dt
thank u for helping
There are no AI answers yet. The ability to request AI answers is coming soon!