Use differentiation to find the taylor series about 0 for the function

Question

g(x)=(1/16+x)^-5/4
giving all terms up to one in x^2, and calculating each coefficient as an integer or a fraction

Answer 1

so, what do you get for g'(x)?

Answer 2

i have no clue

Answer 3

well, assuming you meant

g(x) = (1/16 + x)^(-5/4)
g'(x) = (-5/4)(1/16 + x)^(-9/4)

using the chain rule for g(x) = u^n and u = (1/16 + x)

do that again for g", and evaluate the fractions.

Answer 4

Thanks