Asked by Syam
Find the differentiation of the following function
a) y=5x^4(x-7)^1/2
b) y=(2(x)^1/2-(3))/(x)^1/2+1
a) y=5x^4(x-7)^1/2
b) y=(2(x)^1/2-(3))/(x)^1/2+1
Answers
Answered by
Reiny
Use the product rule for the first and the quotient rule for the second.
1.
y = (5x^4)(x - 7)^(1/2)
dy/dx = (5x^4)(1/2)(x-7)^(-1/2) + 20x^4 (x-7)^(1/2)
I found most students find the difficulty not in finding that first derivative line, but rather in simplifying it
I don't know how far you are expected to take this "first line" derivative.
Let me know before I continue.
1.
y = (5x^4)(x - 7)^(1/2)
dy/dx = (5x^4)(1/2)(x-7)^(-1/2) + 20x^4 (x-7)^(1/2)
I found most students find the difficulty not in finding that first derivative line, but rather in simplifying it
I don't know how far you are expected to take this "first line" derivative.
Let me know before I continue.
Answered by
Syam
For me to simplify the answer is the most difficult. Especially when meet fraction or with surd..
Answered by
Reiny
look for common factors first,
looking at the 5x^4 and 20x^3 , that would be 5x^3
looking at the (x-7)^(-1/2) and (x-7)^(1/2) , that would be (x-7)^(-1/2) , (take the lower exponent one)
also I would take out the fraction of 1/2
= (1/2)(5x^3)(x-7)^(-1/2) [x + (2/1)(4)(x-7) ]
= (5/2)x^3 (x-7)^(-1/2) [ x + 8x - 56]
= 5x^3 (9x - 56)/(2√(x-7) )
looking at the 5x^4 and 20x^3 , that would be 5x^3
looking at the (x-7)^(-1/2) and (x-7)^(1/2) , that would be (x-7)^(-1/2) , (take the lower exponent one)
also I would take out the fraction of 1/2
= (1/2)(5x^3)(x-7)^(-1/2) [x + (2/1)(4)(x-7) ]
= (5/2)x^3 (x-7)^(-1/2) [ x + 8x - 56]
= 5x^3 (9x - 56)/(2√(x-7) )
Answered by
Syam
How you get (2/1) in the []?
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