Asked by Heaven
                A quadratic function has a vertex of (3,-6) and the point (-1,10) lies on the graph of the function. Write the function in standard form. 
If you could help me with this question, that would be great. Thanks in advance.
            
        If you could help me with this question, that would be great. Thanks in advance.
Answers
                    Answered by
            Steve
            
    using the vertex form,
y = a(x-3)^2 - 6
using the point given,
10 = a(-1-3)^2 - 6
10 = 16a-6
a = 1
y = (x-3)^2 - 6 = x^2-6x+3
    
y = a(x-3)^2 - 6
using the point given,
10 = a(-1-3)^2 - 6
10 = 16a-6
a = 1
y = (x-3)^2 - 6 = x^2-6x+3
                    Answered by
            Kamarianna
            
    Which quadratic function in vertex form can be represented by the graph that has a vertex at (3,-7) and passes through the point (1,-10)
    
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