A quadratic function has a vertex of (3,-6) and the point (-1,10) lies on the graph of the function. Write the function in standard form.

If you could help me with this question, that would be great. Thanks in advance.

2 answers

using the vertex form,

y = a(x-3)^2 - 6

using the point given,

10 = a(-1-3)^2 - 6
10 = 16a-6
a = 1

y = (x-3)^2 - 6 = x^2-6x+3
Which quadratic function in vertex form can be represented by the graph that has a vertex at (3,-7) and passes through the point (1,-10)