Asked by Heaven
A quadratic function has a vertex of (3,-6) and the point (-1,10) lies on the graph of the function. Write the function in standard form.
If you could help me with this question, that would be great. Thanks in advance.
If you could help me with this question, that would be great. Thanks in advance.
Answers
Answered by
Steve
using the vertex form,
y = a(x-3)^2 - 6
using the point given,
10 = a(-1-3)^2 - 6
10 = 16a-6
a = 1
y = (x-3)^2 - 6 = x^2-6x+3
y = a(x-3)^2 - 6
using the point given,
10 = a(-1-3)^2 - 6
10 = 16a-6
a = 1
y = (x-3)^2 - 6 = x^2-6x+3
Answered by
Kamarianna
Which quadratic function in vertex form can be represented by the graph that has a vertex at (3,-7) and passes through the point (1,-10)
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