Asked by Victor
Calculate the concentrations of Cd2 +, [Cd (CN) 42] and CN at equilibrium when they dissolve 0, 42mol of
Cd(NO3)2, molarity= 2.50 M
Kf =7.1x10^16
Cd(NO3)2, molarity= 2.50 M
Kf =7.1x10^16
Answers
Answered by
DrBob222
Your post isn't clear to me. I'm confused by the "when THEY dissolve"
What is meant by they?
What is meant by they?