Asked by joy
A rotating flywheel of diameter 48.0 cm uniformly accelerates from rest to 240 rad/s in 15.0 s. Find the linear velocity of a point on the rim of the wheel after 15.0 s. Round answer to one decimal place.
Answers
Answered by
Chloe
The acceleration is centripetal (circular):
a = velocity^2 /radius (formula)
= 240^2 /24
= 2400 rad/s^2
Linear velocity is calculated using the formula v = u + at. That is:
final velocity = initial velocity + acceleration x time
linear velocity = 0 (since at rest) + 2400 x 15
= 36000 rad/s
I'm pretty sure this is what you do, although that final answer is quite large. I'd double check with someone else to be sure.
a = velocity^2 /radius (formula)
= 240^2 /24
= 2400 rad/s^2
Linear velocity is calculated using the formula v = u + at. That is:
final velocity = initial velocity + acceleration x time
linear velocity = 0 (since at rest) + 2400 x 15
= 36000 rad/s
I'm pretty sure this is what you do, although that final answer is quite large. I'd double check with someone else to be sure.
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