Asked by rutuja
a flywheel of mass 200 kg is rotating at the rate of 8 rps . find the constant torque required to stop the disc in 11 rotations.
Answers
Answered by
Damon
during the stop the average speed is 8/2 = 4 rps
11 r/4 r/s = 2.75 seconds to stop
initial angular speed = 2 pi * 8 = 16pi = 50.3 radians/second = Vi
v = Vi + a * t
0 = 50.3 + a * 2.75
a = - 18.3 radians/s^2
Torque = I a = I*= -18.3
I do not know the mass distribution of your flywheel so all I can say is
= something*200 R^2 * -18.3
11 r/4 r/s = 2.75 seconds to stop
initial angular speed = 2 pi * 8 = 16pi = 50.3 radians/second = Vi
v = Vi + a * t
0 = 50.3 + a * 2.75
a = - 18.3 radians/s^2
Torque = I a = I*= -18.3
I do not know the mass distribution of your flywheel so all I can say is
= something*200 R^2 * -18.3
Answered by
Random
Why did u take average speed?
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