Asked by Tiffany
experiment times: .15, .13, .16, .14, .15, .14, .15, .14
so i found the average to be .15
and the highest value was .16
the lowest value was .13
so what is the uncertainty? (in other words... .15 plus or minus what number?) please explain. thanks
so i found the average to be .15
and the highest value was .16
the lowest value was .13
so what is the uncertainty? (in other words... .15 plus or minus what number?) please explain. thanks
Answers
Answered by
bobpursley
On my trusty TI30 calculator, I ran the data as
n=8, sigma(n-1)=.009258, mean=.145
So I don't know how you got your "average"
Three standard deviations would be +-.028
I have no idea what you have defined uncertainity as, three standard deviations is usually plenty.
n=8, sigma(n-1)=.009258, mean=.145
So I don't know how you got your "average"
Three standard deviations would be +-.028
I have no idea what you have defined uncertainity as, three standard deviations is usually plenty.
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