A jet of mass 4,768 kg lands on an airstrip, stopping after a distance of 414 m. If the jet has an initial landing speed of 36 m/s, what is the work done, in Joules, by non-conservative forces to stop the jet?

Answer 1

V^2 = Vo^2 + 2a*d. V = 0, Vo = 36 m/s, d = 414 m, a = ?. a will be negative.

F = M*a. W = F*d Joules.