Asked by Dylan
Determine the pH of a solution made by diluting 25mL of 6.0 M HCl until the final volume of the solution is 1.75 L
Answers
Answered by
DrBob222
mL1 x M1 = mL2 x M2
25 x 6.0 = 1750 mL x M2
Solve for M of diluted HCl.
Then pH = -log (HCl)
25 x 6.0 = 1750 mL x M2
Solve for M of diluted HCl.
Then pH = -log (HCl)
Answered by
Anonymous
0.065
Answered by
anonymous
1.07
Answered by
Ggggggerry
1.1 with sigfigs
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