5 a *c + 5 a *2b + 5 a *5d
= 5 a ( c + 2b + 5d )
by distributive property of multiplication
I'm so confused with the whole factorising process. Please help explain: How do we take out the highest common factors in the expressions: a)5ac+10ab-25ad b)8m-24mn c)30gh+15fg-5fh
3 answers
8m-24mn
m is common and 24 = 8 * 3
so
8 m * 1 - 8 m * 3n
= 8m ( 1-3n)
30gh+15fg-5fh
5 again and I see nothing else common to all three terms
5 ( 6gh + 3fg - 1fh )
m is common and 24 = 8 * 3
so
8 m * 1 - 8 m * 3n
= 8m ( 1-3n)
30gh+15fg-5fh
5 again and I see nothing else common to all three terms
5 ( 6gh + 3fg - 1fh )
5 a *c + 5 a *2b - 5 a *5d
= 5 a ( c + 2b - 5d )
= 5 a ( c + 2b - 5d )