Asked by Misty
Determine whether the sequence converges or diverges. If it converges, find the limit. (If an answer does not exist, enter DNE.)
limit n approaches infinity of an = e^(−6/sqrt(n))
limit n approaches infinity of an = e^(−6/sqrt(n))
Answers
Answered by
Steve
clearly e^(-6/√n) -> e^(-6/∞) = e^0 = 1
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